A particle moves in rectilinear motion such that acceleration – displacement curve is as shown in figure. If initially, s = 0 & v = 4 m/s. What is the velocity when position is
(i) 8m (ii) 12m.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION
Sol. (i)
Area I = 6 × 8 = 48
= 48
v 2 = 4 2 + 96
v 2 = 16 + 96
v = 
= 10.2 m/s.
(ii)
= 
= 
v ′ = 2m/s.
Area of shaded region
= 6 × 8 + 
(6+v ′ ) × 4
= 48 + 
(6 + 2) × 4
= 48 + 16
= 64
v 2 = u 2 + 128
v = 
= 12m/s
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